Hi again out there
As far as I could find in my physics book the
heating of a copper wire with known weight from
its diameter and length, a known applied power and
time will be: dT = (P*t)/(m*c) and T1 = T0 + dT
Example:
P=1W, t=3600s (60min), m=1kg, T0=25
degC and c=387 J/(Kg*K) gives
dT = 9.3 and T1=34.3
degC.
Fine, but what if one has to account for
the heat conductance and heat radiation from the
wire (natural air cooling) - then what will the
final temperature be in degrees Celcius?